Question 1180287
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The full space of events is the set of all combinations of 15 teams taken 8 at a time

    {{{N[total]}}} = {{{C[15]^8}}} = 6435 elements.


The favorable events are those combinations of this set which contain 3 canadian teams.

The number of such combinations is

    {{{N[favorable]}}} = {{{C[15-3]^(8-3)}}} = {{{C[12]^5}}} = 792.


The probability the problem asks for is the ratio

    P = {{{favorable/total}}} = {{{792/6435}}} = {{{8/65}}}.    <U>ANSWER</U>
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Solved, answered and explained.