Question 111011
5x^2+3y^2=17
3y^2=-5x^2+17 (red graph)
-x+y=-1
y=x-1 (green line)
{{{ graph( 300, 200, -6, 5, -10, 20, 3y^2=-5x^2+17, y = x -1) }}} (graph 300x200 pixels, x from -6 to 5, y from -10 to 20, of TWO functions 3y^2 = -5x^2 -17 and y = x -1).
y=x-1
3(x-1)^2=-5x^2+17
3(x^2-2x+1)=-5x^2+17 
3x^2-6x+3=-5x^2+17
3x^2+5x^2-6x+3-17=0
8x^2-6x-14=0 reduce by dividing by 4
2(4x^2-3x-7)=0
2(4x-7)(x+1)=0
4x-7=o
4x=7
x=7/4 answer.
y=7/4-1
y=(7-4)/4
y=3/4 answer 
so the intersection is (7/4,3/4)