Question 1180246

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Calculate mid point of AB and AC

x=(-1+7)/2 =-3
y= (18+4)/2 =11

slope of EF
x1		y1	x2	y2				
-3		11	3	9				
								
slope m =		(y2-y1)/(x2-x1)						
(	9	-	11	)/(	3	-	-3	)
(	-2	/	6	)  				
m=		-0.33						 


slope of BC

x1		y1	x2	y2				
-7		4	5	0				
								
slope m =		(y2-y1)/(x2-x1)						
(	0	-	4	)/(	5	-	-7	)
(	-4	/	12	)  				
m=		-0.33						 

slope EF  equal to slope BC
so EF parallel to BC