Question 1180282
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Since a base is not specified, the base is 10.<br>
a) log(3500)<br>
3500=(5)(7)(10^2)
log(3500)=log(5)+log(7)+2log(10) = log(5)+log(7)+2<br>
b) log(2)<br>
2 =10/5
log(2)=log(10)-log(5)=1-log(5)<br>
Use the given definitions of m and n to write the two logs in terms of m and n.<br>