Question 1180203
x^2+(x+1)^2=61
x^2+x^2+2x+1=61
so 2x^2+2x-60=0
so x^2+x-30=0
(x+6)(x-5)=0
x=-6; and -6 and -5 have squares who add to 61.
x=5, and 5 and 6 do the same

Those are the two pairs of numbers.