Question 1180172
y = 7x-42 and the circle with equation x^2+y^2-4x+6y = 12

substitute y in equation of circle

{{{x^2 +(7x-42)^2-4x+6(7x-42)=12}}}

{{{x^2 +49x^2-588x +1764+42x-252=12}}}

{{{50x^2 -550x +1500=0}}}

{{{ x^2-11x+30=0}}}

(x-6)(x-5)=0

x=6, x=5
plug value of x to get values of y

(6,0), (5,-7)

*[illustration circle.png].