Question 1180051
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Your notation is indeed unclear....<br>
For the problem to make sense, I believe the given expression is this:<br>
{{{log(3,(x-3))-log(1/3,(x+1))}}}<br>
To write this expression using base 9 logs, note<br>
{{{9 = 3^2}}}
and
{{{9 = (1/3)^(-2)}}}<br>
Then<br>
{{{log(3,(x-3))=2log(9,(x-3))}}}
{{{log(1/3,(x+1))=-2log(9,(x+1))}}}<br>
Then<br>
{{{log(3,(x-3))-log(1/3,(x+1)) = 2log(9,(x-3))+2log(9,(x+1))}}}<br>
The expression can then be written in various forms:<br>
{{{2log(9,((x-3)(x+1)))}}}<br>
{{{log(9,((x-3)(x+1))^2)}}}<br>