Question 1180141
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Draw a sketch; then draw the segments connecting the centers of the three circles.<br>
Those three segments will form an equilateral triangle with side length equal to twice the radius of the circles.<br>
The area between the circles is the area of that equilateral triangle, minus the areas of the three "slices of pie" that are the intersections of the triangle and the three circles.<br>
Area of an equilateral triangle with side length s: {{{(s^2*sqrt(3))/4}}}
Area of a circle with radius r: {{{pi*r^2}}}<br>
Note the angles of the equilateral triangle are each 60 degrees, which is 1/6 of a circle.  So the combined areas of the three "slices of pie" is half the area of one of the circles.<br>
You can fill in the details and do the calculations....<br>
(your final answer should be about 64.5)<br>