Question 1180068
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Good luck having a wall of an aquarium with a cross section in the shape of a parabola of the form y^2=ax....!<br>
We can quickly eliminate answer choices a. and b.<br>
Consider the vertex of the parabolic cross section to be at (0,0).  Then, since the dome has a depth of 4 feet and a width of 60 feet, the parabolic function must have the value 4 at x values of 30 and -30.<br>
Use the general form of the equation of a parabola with vertex at the origin to quickly find the answer to the problem.<br>
{{{y = ax^2}}}
{{{4 = a(30^2)}}}<br>
There is little work left to do from there....<br>