Question 1180083
<br>
Use Descartes' rule of signs.<br>
In P(x), there are 3 sign changes; the possible numbers of positive real roots are 3 or 1.<br>
In P(-x), there are 0 sign changes; the number of negative real roots is 0.<br>
ANSWER: There are two possibilities:
(a) 3 positive real roots and one pair of imaginary roots; or
(b) 1 positive real root and two pairs of imaginary roots<br>