Question 1180073

 If the distance covered by an object in time{{{ t}}} is given by 

{{{s(t)=2t^2+3}}}, where {{{s(t) }}}is in meters and{{{ t}}} is in seconds, what is the average velocity over the interval from {{{2 }}}seconds to {{{4 }}}seconds?


The average velocity over an interval [{{{a}}},{{{b}}}] for the position function {{{s(t) }}}can be found by the difference quotient

{{{(s(b)-s(a))/(b-a)}}}

{{{b=4}}} seconds
{{{s(4)=2*4^2+3=35}}}
{{{a=2}}} seconds
{{{s(2)=2*2^2+3=11}}}

the average velocity is 

{{{(s(b)-s(a))/(b-a)=(35-11)/(4-2)=24/2=12}}}



answer: d. {{{12 (meters/second)}}}