Question 1180039
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The money from sales of university tickets was twice the money from sales of primary tickets; and the price of a university ticket was four times the cost of a primary ticket.  That means the number of primary tickets sold was twice the number of university tickets.  Then the given information tells us<br>
x = # of university tickets
2(x) = 2x = # of primary tickets
4(2x) = 8x = # of secondary tickets<br>
The total price of the tickets sold was 22000:<br>
{{{400(x)+200(8x)+100(2x) = 2200x = 22000}}}
{{{x = 22000/2200 = 10}}}<br>
So the numbers of tickets sold were
x = 10 university tickets
2x = 20 primary tickets
8x = 80 secondary tickets<br>
CHECK:
10(400)+20(100)+80(200) = 4000+2000+16000 = 22000<br>
Note the answer to the problem as presented is the (total) number of tickets sold....<br>
ANSWER: 10+20+80 = 110 tickets were sold<br>