Question 1180018
.
<pre>

It is the probability of getting two tails and two heads of 4 flips in any order


    P(2T2H of 4) = {{{C[4]^2*(1/2)^2*(1/2)^2}}} = {{{((4*3)/(1*2))*(1/2)^4}}} = 0.375.     <U>ANSWER</U>
</pre>

Solved.



Do not forget to post your "THANKS" to me for my teaching.