Question 1180007
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(a)  t = v/g,  v is initial velocity (2 m/s);  g is the gravity acceleration (10 m/s^2).


     So, t = 2/10 = 0.2 seconds.


     " How high "   is  the product of the time of 0.2 seconds by the average speed of 2/2 = 1 m/s, i.e.  0.2*1 = 0.2 meters.



(b)  Two times this time: 0.2 seconds + 0.2 seconds = 0.4 seconds.



(c)  the speed of the orange at the caugh moment is the same as the initial speed, 2 m/s  (energy conservation law)
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Solved.


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