Question 1179980
yes,  it is {{{9050.25}}}->congratulations!


{{{A = P(1 + r/n)^(nt)}}}

{{{r=0.05}}}
{{{A=10000}}}
{{{n=12}}}
{{{t=2}}}

{{{10000 = P(1 + 0.05/12)^(12*2)}}}

{{{10000 = P(1.0041666666666667)^24}}}

{{{10000 = P(1.1049413355583281)}}}

{{{P=10000/(1.1049413355583281)}}}

{{{P=9050.25}}}