Question 1179963
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Ignoring the alternating signs for the moment...<br>
term #1 is 0
term #2 is 1
term #3 is 2
term #4 is 3
...
term #n is (n-1)<br>
To get the alternating signs, add a factor of (-1)^n or (-1)^(n-1) to the formula.  Since the even-numbered terms are positive, we need a factor of (-1)^n.<br>
ANSWER: {{{t(n) = ((-1)^n)(n-1)}}}<br>