Question 1179940
Robert has some nickels and dimes worth $1.85. He has 11 more dimes than nickels. How many of each type does he have?

let number of nickels be x
and dimes be y

y=x+11


5x+10y = 185    (cents)
substitute y 

5x +10(x+11) =185

15x +110=185
15x = 75
x =5 nickels
plug x in y=x+11