Question 1179883
We are given that f(x)-f(x+1)=3x^2
f(3)=48
Put x=3
We get f(3)-f(4)=3(3)^2
48-f(4)=27
f(4)=48-27=21
Put x=4 in the original equation
We get f(4)-f(5)=3(4)^2
21-f(5)=48
f(5)=21-48=-27
The value of f(5) is -27.