Question 1179912

{{{a =-2}}}, {{{b = 6}}}, {{{c =-3}}}, and {{{d = 4}}}


{{{-5/(6b)+1/(2(ac + bd))}}}


={{{-5/(6*6)+1/(2(-2(-3) + 6*4))}}}


={{{-5/36+1/(2(6 + 24))}}}


={{{-5/36+1/(2(30))}}}


={{{-5/36+1/60}}}


={{{-11/90}}}