Question 1179842
Given the following date: {{{8}}},{{{5}}},{{{6}}},{{{10}}},{{{8}}},{{{3}}},{{{6}}} find the


A. Median

The median is the value separating the higher half of the data set, from the lower half.
If the number of terms is odd, then the median is the middle ellement of the sorted set.
If the number of terms is even, then the median is the arithmetic mean of the two middle elements of the sorted set.

sorted set:
{{{3}}},{{{5}}},{{{6}}},|{{{highlight(6)}}}|,{{{8}}},{{{8}}},{{{10}}}


Median={{{highlight(6)}}}



B.Sample Mean

mean(average) is the sum of the values in the set divided by the number of elements in that set

mean={{{(3+5+6+6+8+8+10)/7=46/7=6.571428571}}}



C.Sample Standard Deviation

Standard Deviation is the square root of variance, so compute variance

Explanation
First, I added up all of the numbers: 
{{{3 + 5 + 6 + 6 + 8 + 8 + 10 = 46}}}

I squared the total, and then divided the number of items in the data set 
{{{46^2/7 = 2116/7= 302.2857142857143}}}

I took my set of original numbers from step 1, squared them individually this time, and added them all up:

{{{3^2 + 5^2 + 6^2+ 6^2+ 8^2 + 8^2 + 10^2 = 334}}}

I subtracted the amount in step 2 from the amount in step 3:

{{{334 - 302.2857142857143 = 31.714285714285722}}}

I subtracted 1 from the number of items in my data set:{{{7 - 1 = 6}}}

I divided the number in step 4 by the number in step 5:

{{{31.714285714285722 / 6 = 5.28571428571}}}=>This is my Variance!

Finally, I took the square root of the number from step 6 (the Variance),
{{{sqrt(5.285714285714287) = 2.2990681}}}=>This is my Standard Deviation!