Question 1179837
.
Find the equation of the circle that passes through the point P(5, 2) and whose center is the point C(3, 4). 
~~~~~~~~~~~~~


<pre>
The vector from the center to the point is 2 units (5-3 = 2) along x- axis  and (-2) units (2-4 = -2) along y-axis.


Hence, the radius of the circle is  r = {{{sqrt(2^2 + (-2)^2)}}} = {{{sqrt(8)}}}.


Thus the equation of the circle is


    {{{(x-3)^2}}} + {{{(y-4)^2}}} = 8.    <U>ANSWER</U>
</pre>

Solved.