Question 1179770
Find the point that {{{y=(3/2)x+5}}} intersects with {{{cross(y=-(2/3)x-3)}}}.   Use the Distance Formula to find distance from this point and  (3,5).



The line of slope  {{{-2/3}}}  with the point  (3,5):
{{{y-5=(-2/3)(x-3)}}}
{{{y-5=-2x/3+2}}}
{{{y=-2x/3+7}}}

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