Question 1179759
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Hi
Normal Distribution: µ = 74 and σ = 7
11.9% of the class is given X’s score

 .0595 above and below the mean: .5 + .0595 = .5595
invNorm(.5595,74,7) = 75

the highest possible score X is 75  (1 to the right of mean 74)
lowest is 74 - 1 = 73

Your Reference did not work for me.
If the intent was for 11.9% to get As...
invNorm(.881,74,7) = 82.26  Round Up to next whole number
or 
{{{blue(sigma)*z + mu=blue (x)}}}   {{{z*(blue(sigma)) + mu=blue (x)}}}
 7*1.18 + 74 = 82.26  Round Up to next whole number
 
For As:  lowest is 83  and highest, would be a possible 100.
Wish You the Best in your Studies.
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