Question 1179754


b. 

{{{f(x)= 4x^2 + 4x - 15}}}......equal to zero

{{{ 4x^2 + 4x - 15=0}}}....factor

{{{ 4x^2 -6x+ 10x - 15=0}}}

{{{ (4x^2 -6x)+ (10x - 15)=0}}}

{{{ 2x(2x -3)+ 5(2x - 3)=0}}}

 {{{(2 x - 3) (2 x + 5)=0}}}

solutions:
{{{(2 x - 3) =0}}}=>{{{x=3/2}}}
{{{ (2 x + 5)=0}}}=>{{{x=-5/2}}}

so, since {{{x=m}}}

{{{m [1]=3/2}}}
{{{m [2]=-5/2}}}