Question 1179756
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Hi
the vertex form of a Parabola opening up(a>0) or down(a<0), 
{{{y=a(x-h)^2 +k}}} 
where(h,k) is the vertex  and  x = h  is the Line of Symmetry 
Question States:  y = a(x-1)^2 - 6  x = 1 line of symmetry

P(-2,4) and P(4,4) are both 3 from the line of symmetry.

Wish You the Best in your Studies.
y = (10/9)(x-1)^2  - 6
{{{drawing(300,300,    -10,10,-10,10,  blue(line(1,10,1,-10))  ,  
 grid(1),
circle(4, 4,0.4),
circle(-2,4,0.4),
circle(1,-6,0.4),
graph( 300, 300, -10,10,-10,10,0, (10/9)(x-1)^2  - 6))}}}

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