Question 1179758

there were 24 nickles, dimes, and quarters whose total value equaled $4.25. 

n+d+q=24

5n+10d+25q= 425 
n=d


n+d+q=24
d+d+q=24
2d+q=24

5n+10d+25q= 425 
5d+10d+25q=425
15d+25q =425

	d	dimes										
	q	quarters										
												
												
2.00	d	+	1.00	q	=	24.00						
												
												
15.00	d	+	25.00	q	=	425.00	.............2					
Eliminate 	q											
multiply (1)by		-25.00										
Multiply (2) by		1.00										
-50.00	d		-25.00	q	=	-600.00						
15.00	d		25.00	q	=	425.00						
Add the two equations												
-35.00	d				=	-175.00						
/	-35.00											
d	=	5.00										
plug value of			d	in (1)								
2.00	d	+	1.00	q	=	24.00						
10.00		+	1.00	q	=	24.00						
			1.00	q	=	14.00						
				q	=	14.00						
Ans	d	=	5									
	q	=	14									
	5	dimes										
	14	quarters