Question 1179710

{{{4x − 3y = 7}}}....eq.1
{{{3x − 4y = −7}}}....eq.2
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{{{4x − 3y = 7}}}....eq.1......solve for {{{x}}}

{{{4x = 3y+7}}}

{{{x = 3y/4+7/4}}}.........1a)


{{{3x − 4y = −7}}}....eq.2......solve for {{{x}}}

{{{3x =4y −7}}}

{{{x =4y/3 −7/3}}}........1b)


from 1a) and 1b) we have

{{{3y/4+7/4=4y/3 −7/3}}}
 
{{{7/3+7/4=4y/3 −3y/4}}}

{{{49/12=(7y)/12}}}

{{{49=7y}}}

{{{y=7}}}

go to

{{{x = (3*7)/4+7/4}}}.........1a)

{{{x = (4*7)/4}}}

{{{x = 7}}}


{{{ drawing( 600, 600, -10, 10, -10, 10,
circle(7,7,.12),locate(7,7,p(7,7)),
graph( 600, 600, -10, 10, -10, 10, 4x/3-7/3, 3x/4+7/4)) }}}