Question 1179681


{{{x + 2y = 18}}}.......eq.1
{{{-3x + 2y = 10}}}.......eq.2
----------------------------------subtract

{{{x + 2y -(-3x + 2y )= 18-10}}}

{{{x + 2y +3x - 2y = 8}}}

{{{4x = 8}}}

{{{x = 2}}}


go to

{{{x + 2y = 18}}}.......eq.1, substitute {{{x}}}

{{{2 + 2y = 18}}} 

{{{2y = 18-2}}}
 
{{{2y = 16}}} 

{{{y = 8}}} 


The solution to the system of linear equations below is the point ({{{2}}}, {{{8}}}). 


{{{drawing( 600,600, -10, 10, -10, 10,
circle(2,8,.12), locate(2,8,p(2,8)),

 graph( 600,600, -10, 10, -10, 10, (18-x)/2,(3x+ 10)/2)) }}}