Question 1179657


the current in the ogeechee river flowed at 5 miles per hour. the boat could go 160 miles downstream in twice the time it took to go 40 miles upstream. what was the speed of the boat in still water, and what were the times?

speed of boat in still water =x mph
current speed = 5mph

with current (x+5) mph====> 160 miles
against current  speed (x-5)mph=====> 40 miles

160/(x+5) = 2*40/(x-5)

2/(x+5) = 1/(x-5)

2(x-5) =x+5
2x-10=x+5
x=15 mph speed of boat in still water