Question 1179662


Divide 75 into two parts so that one part is 2/3 of the other.

let  two parts be {{{x}}} and {{{y}}}

given:

{{{x+y=75}}}...eq.1
and
{{{x=(2/3)y}}}....eq.2, substitute in eq.1

{{{(2/3)y+y=75}}}...eq.1, solve for {{{y}}}

{{{2y/3+3y/3=75}}}
{{{5y/3=75}}}
{{{5y=75*3}}}
{{{y=(75*3)/5}}}
{{{y=15*3}}}
{{{y=45}}}

go to

{{{x+y=75}}}...eq.1
{{{x+45=75}}}
{{{x=75-45}}}
{{{x=30}}}

so, one part is {{{30}}} and other part is {{{45}}}