Question 1179614
Is it possible to get infinitely many solutions and an x, y, and z value for the following problem. Solve the system of equations using elimination.
a. -4x+5y-3z=17
b. -3x-2y-4z=-1
c. 5x+5y+4z=12
a*-2= 8x-10y+6z=-34
c*2= 10x+10y+8z=24
equation d: 18x+14z=-10
-4x+5y-3z=17
-5x-5y-4z=-12
equation e: -9x-7z=5
e*2 -18x-14z=10
d 18x+14z=-10
result 0=0 infinitely many
I solved another way and got x=1, x=3, and x=-2
Assuming you meant x, y, and z:
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Sub your numbers and see if they work.
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a. -4x+5y-3z=17
-4*1 + 5*3 - 3*-2 = -4 + 15 + 6 = 17
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b. -3x-2y-4z=-1
-3*1 -2*3 - 4*-2 = -3 -6 +8 = -1 
c. 5x+5y+4z=12
5*1 + 5*3 + 4*-2 = 5 + 15 - 8 = 12
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Your solution is correct, so there is a unique solution to the system.
It's not possible to get an infinite # of solutions.