<PRE><B>Question 1179514</B>
Given the vertices of a triangle are P (3,7), Q(-8,2) and R(-4,-9). Determine the equation of the altitude that passes through the point P.

Slope of QR = m= (y2-y1)/(x2-x1)

(-9-2)/(-4-(-8)) = -11/4

The slope of the altitude will be 4/11    ( negative reciprocal because the lines are perpendicular)

P(3,7) slope = 4/11

Plug value of  the slope  and point	(	3	,	7	) in
Y	=	m	x	+	b		
7.00	=	1    	+	b			
b=	7.00	-	1  1/11				
b=	5 10/11						
So the equation  will be							
Y 	=	  4/11	x	+	5 (10/11)		

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