Question 1179517
Standard Form of an Equation of a Circle is {{{(x-h)^2 + (y-k)^2 = r^2}}} 
where Pt(h,k) is the center and r is the radius
x^2 + y^2 + 6x + 8y + 25 = 16
0r
(x+3)^2 + (y+4)^2 - 9 - 16 + 25 = 16
(x+3)^2 + (y+4)^2 = 16 = r^2
C(-3, -4)  and r = 4