Question 1179515
Standard Form of an Equation of a Circle is {{{(x-h)^2 + (y-k)^2 = r^2}}} 
where Pt(h,k) is the center and r is the radius
(5, 0); 4

{{{(x-5)^2 + (y-0)^2 = 4^2}}} 
{{{(x-5)^2 + y^2 = 16}}} is the circle with the given center and radius.