Question 1179450
Write the standard form of the equation of the circle with the given center and radius.

({{{0}}}, {{{-5}}})
{{{r=11}}}

the standard form of the equation of the circle is:

{{{(x-h)^2+(y-k)^2=r^2}}}.........given ({{{0}}}, {{{-5}}})=> {{{h=0}}} and {{{k=-5}}}, and {{{r=11}}}

{{{(x-0)^2+(y-(-5))^2=11^2}}}

{{{x^2+(y+5)^2=121}}}-> answer


{{{ drawing( 600, 600, -25, 25, -25, 25,
circle(0,-5,.35),locate(0.3,-5,C(0,-5)),

graph( 600, 600, -25, 25, -25, 25,-sqrt(-x^2+121)-5 , sqrt(-x^2+121)-5)) }}}