Question 110908
Find the corresponding values of y in {{{y = x^2-x-2}}} for x = -2, -1, 0, 1, 2, 3.

I'll do a couple of these and you should be able to finish:

{{{y = x^2-x-2}}} Substitute x = -2.
{{{y = (-2)^2-(-2)-2}}}
{{{y = 4 + 2 - 2}}}
{{{y = 4}}}

{{{y = x^2-x-2}}} Substitute x = -1.
{{{y = (-1)^2-(-1)-2}}}
{{{y = 1 + 1 -2}}}
{{{y = 2-2}}}
{{{y = 0}}}
Just continue in this fashion!