Question 1179386
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<pre>

    {{{y[1]}}} = 1;   {{{y[n]}}} - {{{y[n-1]}}} = n,   n = 2, 3, 4, . . . ,


or, which is the same,


    {{{y[1]}}} = 1;   {{{y[n]}}} = {{{y[n-1]}}} + n,   n = 2, 3, 4, . . . 


It is the recursive formula the problem requests for.
</pre>

Solved, answered and explained.