Question 1179368


if the width of a rectangle is {{{3ft}}}  less than the length, then we have 

{{{W=L-3ft}}}....eq.1

if the area of the rectangle is {{{88ft^2}}}, we have

{{{L*W=88}}}........substitute {{{W}}}

{{{L*(L-3)=88}}}

{{{L^2-3L=88}}}

{{{L^2-3L-88=0}}}...factor

{{{L^2-11L+8L-88=0}}}

{{{(L^2-11L)+(8L-88)=0}}}

{{{L(L-11)+8(L-11)=0}}}

{{{(L - 11) (L + 8) = 0}}}

=>{{{L=11}}} or {{{L=-8}}}-> disregard negative solution for length


go to

{{{W=L-3}}}....eq.1, substitute {{{L=11}}} 

{{{W=11-3}}}

{{{W=8}}}



the length of the rectangle {{{L=11ft}}} and width of the rectangle{{{W=8ft}}}