Question 1179286
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            If in a test or in exam you will solve the problem in a way how  @Mathlover1  does it 

            and teaches you,  you will get an  UNSATISFACTORY  score  MOMENTARILY.


            I came to solve this problem in a proper way,  how it  SHOULD  BE  done.



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(1)  1/sin(x) = 1/cos(y).



     It implies that sin(x) = cos(y),  which means that x + y = {{{pi/2}}},

     or, equivalently,  y = {{{pi/2 -x}}}.



Part (2) is the same.
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Solved &nbsp;&nbsp;// &nbsp;&nbsp;(correctly)