Question 1179305
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To see the answer, go to wolframalpha.com and enter the expression in the box.<br>
To get the answer using the binomial theorem is a straightforward process; you can do it yourself.<br>
Think of the expression like this:<br>
{{{(2y-5)(2y-5)(2y-5)}}}<br>
The product is going to be obtained by finding all the partial products resulting from picking one of the two terms from each of the three identical factors.<br>
I hope it is clear that the answer is going to have terms in y^3, y^2, and y, plus a constant.<br>
Here are where the different terms come from....<br>
To get the y^3 term we need to choose the "2y" term from all 3 of the 3 factors.  The y^3 term is<br>
{{{C(3,3)((2y)^3)((-5)^0)}}}<br>
To get the y^2 term we need to choose the "2y" term from 2 of the 3 factors and the "-5" term from the other.  The y^2 term is<br>
{{{C(3,2)((2y)^2)((-5)^1)}}}<br>
To get the y term we need to choose the "2y" term from 1 of the 3 factors and the "-5" term from the other two.  The y term is<br>
{{{C(3,1)((2y)^1)((-5)^2)}}}<br>
To get the constant term we need to choose the "-5" term from all 3 of the 3 factors.  The constant term is<br>
{{{C(3,0)((2y)^0)((-5)^3)}}}<br>
Do all those calculations and compare your answer with the answer from wolframalpha.com.<br>
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