Question 1179277
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<pre>

You calculate the volume of the large (whole) pyramid first

    V = {{{(1/3)*10^2*18}}} = 600 m^3.         (1)



From it, you subtract the volume of the small cut pyramid, which is

   {{{(1/6)^3*600}}} = 2.778 m^3   (rounded).       (2)   



You will get finally for the volume of the frustum

   {{{V[frustum]}}} = 600 - 2.778 = 577.222 m^3  (rounded).     (3)    <U>ANSWER</U>




      The volume of the small pyramid is  {{{(1/6)^3}}} = {{{1/216}}}  
      of the volume of the large pyramid since they are SIMILAR 
      solid bodies with the coefficient of similarity  {{{1/6}}} = {{{3/18}}}.
</pre>

Solved.



In solving this simple problem, you do not need to make many boring calculations 
if you know this basic and useful property of the volumes of similar solid bodies.