Question 1179267
<br>
{{{2log(3,y) = log(3,y^2)}}}<br>
{{{3log(3,x+2) = log(3,(x+2)^3)}}}<br>
So the equation is<br>
{{{log(3,y^2)-4=log(3,(x+2)^3)}}}<br>
Write the "4" as {{{log(3,3^4)}}}<br>
Then<br>
{{{log(3,y^2)-log(3,3^4)=log(3,(x+2)^3)}}}<br>
Now use rules of logarithms to write the expression on the left as a single logarithm.  The equation is now of the form {{{log(3,A)=log(3,B)}}}, which means A=B.<br>
You should be able to finish from there.<br>