Question 1179196


1.  {11,7,3,-1,-5...}

We see that the common difference of the sequence is {{{-4}}}, 


your formula is:

{{{a[n]=11-4(n-1)}}}


2. 2.{76.8,96,120,150...}

{{{96/76.8=5/4}}}

{{{120/96=5/4}}}=> {{{r=5/4}}}


since {{{a[1]=76.8}}} and {{{r=5/4}}}, nth term formula

{{{a[n]=76.8*(5/4)^(n-1)}}}