Question 1179198


the sequence is arithmetic

{{{a[14]= 16}}} and {{{d= -3/2}}}

{{{a[n]=a[1]+(-3/2)(n-1)}}}.........use {{{a[14]= 16}}} to find {{{a[1]}}}

{{{16=a[1]+(-3/2)(14-1)}}}

{{{16=a[1]-(3/2)(13)}}}

{{{16=a[1]-39/2}}}

{{{16+39/2=a[1]}}}

{{{highlight(a[1]=71/2)}}}

and your formula is:

{{{a[n]=71/2+(-3/2)(n-1)}}}