Question 1179170
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<pre>

(a)  There are 7 letters, in all.

     Of them, letter "C" has multiplicity 2, and

              letter "N" has multiplicity 2.


     THEREFORE, the formula and the answer for this question are

         {{{7!/(2!*2!)}}} = {{{(1*2*3*4*5*6*7)/(2*2)}}} = 1260.    <U>ANSWER</U>
</pre>

Solved, answered and explained.


See the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =https://www.algebra.com/algebra/homework/Permutations/Arranging-elements-of-sets-containing-undistinguishable-elements.lesson>Arranging elements of sets containing indistinguishable elements</A> 

in this site.



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<pre>
(b)   {{{8!/8}}} = 7! = 7*6*5*4*3*2*1 = 5040 different ways.    <A>ANSWER</U>
</pre>

Solved.


See the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =https://www.algebra.com/algebra/homework/Permutations/Persons-sitting-around-a-circular-table.lesson>Persons sitting around a cicular table</A> 

in this site, &nbsp;and learn the subject from there.



Also, &nbsp;you have this free of charge online textbook in ALGEBRA-II in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-II - YOUR ONLINE TEXTBOOK</A>.


The referred lessons are the part of this online textbook under the topic &nbsp;"<U>Combinatorics: Combinations and permutations</U>". 



Save the link to this textbook together with its description


Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson


into your archive and use when it is needed.