Question 1179145
<br>
The differences are the same, so the three numbers form an arithmetic progression.<br>
For three number in arithmetic progression with a sum of 120, the middle number is 120/3 = 40; with a common difference of 5, the three numbers are 35, 40, and 45.<br>
ANSWER: Chin $35; Ram $40; Tom $45<br>
If you want a typical standard algebraic solution....<br>
let x = amount Ram gets
then x-5 = amount Chin gets
and x+5 = amount Tom gets<br>
The total is $120:<br>
x + (x-5) + (x+5) = 120
3x = 120
x = 120/3 = 40<br>
ANSWERS: Ram x=40; Chin x-5=35; Tom x+5=45<br>