Question 1179071
<br>
None of the functions are inverses of each other.  Don't be confused by the absurd response from the other tutor, in which she says that f^-1(x)=x-5/2 and that is equal to h(x), which is x-2/5.  The way I learned math, 5/2 and 2/5 are not the same....<br>
I would never find the inverses of these functions using the formal process of switching the x and y and solving for the new y.<br>
All of these functions are simple enough that you can find the inverses using the concept that the inverse function "un-does" what the function does.<br>
f(x)= x+5/2: the rule for the function is "add 5/2"; the rule for the inverse is "subtract 5/2".  f^-1(x) = x-5/2.<br>
g(x) = 2x+5: the rule for this function is "multiply by 2 then add 5"; the rule for the inverse is "subtract 5 and then divide by 2".  g^-1(x) = (x-5)/2.<br>
h(x) = x-2/5: the rule for this one is "subtract 2/5"; the rule for the inverse is "add 2/5".  h^-1(x) = x+2/5.<br>
None of the functions has an inverse that is one of the other functions....<br>