Question 1179101


{{{g(t)=90-15log(10,(t+1))}}}, {{{0 <=t<=24}}}


A) what is the average score on the original exam?


that is when {{{t=0}}}

Average score is

{{{ g(0) = 90 - 15log(10,(0+1))}}}

 {{{ g(0)= 90 - 15log(10,(1)) }}}

{{{ g(0)= 90 - 15*0 }}}

{{{ g(0)= 90 }}}



B) what was the average score after {{{6}}} months?

that is when {{{t=6}}}

Average score is

{{{ g(6) = 90 - 15log(10,(6+1))}}}

 {{{ g(6)= 90 - 15log(10,(7)) }}}

{{{ g(6)= 90 - 15*0.8451}}}

{{{ g(6)= 77.32}}}



C) what was the average score after {{{18}}} months?


that is when {{{t=18}}}

Average score is

{{{ g(18) = 90 - 15log(10,(18+1))}}}

 {{{ g(18)= 90 - 15log(10,(19)) }}}

{{{ g(18)= 90 - 15*1.2787536}}}

{{{ g(18)= 70.82}}}