Question 1179096

3x + 3y = 3
divide by 3
x+y=1
x=1-y

-3x - 2z = -11 
substitute x=1-y in above
-3(1-y)-2z =-11
-3+3y-2z=-11
3y-2z =-8


3y-2z =-8-------------1
y+z=-1
multiply by 2 and add to the equation above
2y+2z=-2--------------2
5y=-10
y=-2

plug y=-2 in y+z=-1
z=1

x+y=1 given
x+ -2 = 1
x=3

x=3,y=-2, z=1