Question 16555
f(x)=2x+1
f(3)+f(2). 
 to get f(3) you have to substitute 3 inplace of x in the given function .hence 
f(3)=2*3+1=7
f(2)=2*2+1=5
 f(3)+f(2)=7+5=12
 Find the domain and range of f(x)= 1/x-4. I know the domain is x and the range is y, but how do I figure it on a fraction?
 domain of a function means the value x can take to make the function meaningfull or legal mathematically...for example in maths division by zero has no meaning.similarly square root of a negative number does not exist.
 here we have 1/(x-4)..which has a division ..so x-4 cannot be zero..so x cannot be equal to 4...so the domain of x is all values of real numbers except 4
      now coming to range it is those values of y ,that are obtained by taking all possible value of x in its domain as determined above.
      here we find that y can take all values of real numbers since x will not equal 4 in the domain.so range of y is all possible values of real numbers